Distance between Linton and Sebastopol
The distance from Linton to Sebastopol is 28 kilometers by road. Road takes approximately 46 minutes.
| Shortest distance by air | 26 km ✈️ |
| Car route length | 28 km 🚗 |
| Driving time | 46 min |
| Fuel amount | 2.3 L |
| Fuel cost | 3.7 AUD |
| Point | Distance | Time | Fuel | |
| Linton | 0 km | 00 min | 0.0 L | |
|
B160 28 km, 46 min
|
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| Sebastopol | 28 km | 46 min | 2.2 L | |
Hotels of Sebastopol
Frequently Asked Questions
How much does it cost to drive from Linton to Sebastopol?
Fuel cost: 3.7 AUD
This fuel cost is calculated as: (Route length 28 km / 100 km) * (Fuel consumption 8 L/100 km) * (Fuel price 1.64 AUD / L)
You can adjust fuel consumption and fuel price here.
How long is a car ride from Linton to Sebastopol?
Driving time: 46 min
This time is calculated for driving at the maximum permitted speed, taking into account traffic rules restrictions.
- 9 km with a maximum speed 90 km/h = 6 min
- 5 km with a maximum speed 80 km/h = 3 min
- 1 km with a maximum speed 60 km/h = 1 min
- 1 km with a maximum speed 50 km/h = 1 min
- 11 km with a maximum speed 20 km/h = 33 min
The calculated driving time does not take into account intermediate stops and traffic jams.
How far is Linton to Sebastopol by land?
The distance between Linton and Sebastopol is 28 km by road.
Precise satellite coordinates of highways were used for this calculation. The start and finish points are the centers of Linton and Sebastopol respectively.
Where is Linton in relation to Sebastopol?
Linton is located 26 km south-west of Sebastopol.
Linton has geographic coordinates: latitude -37.68699, longitude 143.56213.
Sebastopol has geographic coordinates: latitude -37.59868, longitude 143.83588.
Which highway goes from Linton to Sebastopol?
The route from Linton to Sebastopol follows B160.