Distance between Palmarito and San Fernando de Apure
The distance from Palmarito to San Fernando de Apure is 475 kilometers by road. Road takes approximately 5 hours and 58 minutes and goes through Elorza, Mantecal and Apurito.
| Shortest distance by air | 298 km ✈️ |
| Car route length | 475 km 🚗 |
| Driving time | 5 h 58 min |
| Fuel amount | 38 L |
| Fuel cost | 68.7 AUD |
| Point | Distance | Time | Fuel | |
| Palmarito | 0 km | 00 min | 0.0 L | |
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T-19 200 km, 2 h 31 min
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| Elorza | 200 km | 2 h 31 min | 12.1 L | |
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T-19 56 km, 41 min
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| Mantecal | 255 km | 3 h 13 min | 19.9 L | |
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T-19 109 km, 1 h 21 min
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| Apurito | 364 km | 4 h 34 min | 21.0 L | |
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T-19 111 km, 1 h 23 min
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| San Fernando de Apure | 475 km | 5 h 58 min | 37.6 L | |
Frequently Asked Questions
How much does it cost to drive from Palmarito to San Fernando de Apure?
Fuel cost: 68.7 AUD
This fuel cost is calculated as: (Route length 475 km / 100 km) * (Fuel consumption 8 L/100 km) * (Fuel price 1.81 AUD / L)
You can adjust fuel consumption and fuel price here.
How long is a car ride from Palmarito to San Fernando de Apure?
Driving time: 5 h 58 min
This time is calculated for driving at the maximum permitted speed, taking into account traffic rules restrictions.
- 468 km with a maximum speed 80 km/h = 5 h 51 min
- 6 km with a maximum speed 50 km/h = 7 min
The calculated driving time does not take into account intermediate stops and traffic jams.
How far is Palmarito to San Fernando de Apure by land?
The distance between Palmarito and San Fernando de Apure is 475 km by road.
Precise satellite coordinates of highways were used for this calculation. The start and finish points are the centers of Palmarito and San Fernando de Apure respectively.
How far is Palmarito to San Fernando de Apure by plane?
The shortest distance (air line, as the crow flies) between Palmarito and San Fernando de Apure is 298 km.
This distance is calculated using the Haversine formula as a great-circle distance between two points on the surface of a sphere. The start and finish points are the centers of Palmarito and San Fernando de Apure respectively. Actual distance between airports may be different.
How many hours is Palmarito from San Fernando de Apure by plane?
Boeing 737 airliner needs 22 min to cover the distance of 298 km at a cruising speed of 800 km/h.
Small plane "Cessna 172" needs 1 h 21 min to flight this distance at average speed of 220 km/h.
This time is approximate and do not take into account takeoff and landing times, airport location and other real world factors.
How long is a helicopter ride from Palmarito to San Fernando de Apure?
Fast helicopter "Eurocopter AS350" or "Hughes OH-6 Cayuse" need 1 h 14 min to cover the distance of 298 km at a cruising speed of 240 km/h.
Popular "Robinson R44" needs 1 h 25 min to flight this distance at average speed of 210 km/h.
This time is approximate and do not take into account takeoff and landing times, aerodrome location and other real world factors.
What city is halfway between Palmarito and San Fernando de Apure?
The halfway point between Palmarito and San Fernando de Apure is Mantecal. It is located about 18 km from the exact midpoint by road.
The distance from Mantecal to Palmarito is 255 km and driving will take about 3 h 13 min. The road between Mantecal and San Fernando de Apure has length 219 km and will take approximately 2 h 45 min.
The other cities located close to halfway point:
Where is Palmarito in relation to San Fernando de Apure?
Palmarito is located 298 km west of San Fernando de Apure.
Palmarito has geographic coordinates: latitude 7.62049, longitude -70.16326.
San Fernando de Apure has geographic coordinates: latitude 7.87879, longitude -67.47178.
Which highway goes from Palmarito to San Fernando de Apure?
The route from Palmarito to San Fernando de Apure follows T-19, Local 3.
Other minor sections pass along the road:
- T-02: 7 km