Distance between San Fernando de Apure and Mantecal

The distance from San Fernando de Apure to Mantecal is 214 kilometers by road. Road takes approximately 2 hours and 41 minutes and goes through Apurito.

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Town
Village
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Motorway
Primary
Secondary
Unclassified
Point Distance Time Fuel
San Fernando de Apure 0 km 0:00 00 min 0.0 L
T-19 111 km, 1 h 23 min
Apurito 111 km 1:23 1 h 23 min 0.7 L
T-19 104 km, 1 h 17 min
Mantecal 214 km 2:41 2 h 41 min 17.0 L

Frequently Asked Questions

How much does it cost to drive from San Fernando de Apure to Mantecal?

Fuel cost: 30 AUD

This fuel cost is calculated as: (Route length 214 km / 100 km) * (Fuel consumption 8 L/100 km) * (Fuel price 1.75 AUD / L)

You can adjust fuel consumption and fuel price here.

How long is a car ride from San Fernando de Apure to Mantecal?

Driving time: 2 h 41 min

This time is calculated for driving at the maximum permitted speed, taking into account traffic rules restrictions.

  • 212 km with a maximum speed 80 km/h = 2 h 38 min
  • 2 km with a maximum speed 50 km/h = 2 min

The calculated driving time does not take into account intermediate stops and traffic jams.

How far is San Fernando de Apure to Mantecal by land?

The distance between San Fernando de Apure and Mantecal is 214 km by road.

Precise satellite coordinates of highways were used for this calculation. The start and finish points are the centers of San Fernando de Apure and Mantecal respectively.

How far is San Fernando de Apure to Mantecal by plane?

The shortest distance (air line, as the crow flies) between San Fernando de Apure and Mantecal is 188 km.

This distance is calculated using the Haversine formula as a great-circle distance between two points on the surface of a sphere. The start and finish points are the centers of San Fernando de Apure and Mantecal respectively. Actual distance between airports may be different.

How many hours is San Fernando de Apure from Mantecal by plane?

Boeing 737 airliner needs 14 min to cover the distance of 188 km at a cruising speed of 800 km/h.

Small plane "Cessna 172" needs 51 min to flight this distance at average speed of 220 km/h.

This time is approximate and do not take into account takeoff and landing times, airport location and other real world factors.

How long is a helicopter ride from San Fernando de Apure to Mantecal?

Fast helicopter "Eurocopter AS350" or "Hughes OH-6 Cayuse" need 47 min to cover the distance of 188 km at a cruising speed of 240 km/h.

Popular "Robinson R44" needs 53 min to flight this distance at average speed of 210 km/h.

This time is approximate and do not take into account takeoff and landing times, aerodrome location and other real world factors.

What city is halfway between San Fernando de Apure and Mantecal?

The halfway point between San Fernando de Apure and Mantecal is Apurito. It is located about 4 km from the exact midpoint by road.

The distance from Apurito to San Fernando de Apure is 111 km and driving will take about 1 h 23 min. The road between Apurito and Mantecal has length 104 km and will take approximately 1 h 17 min.

Where is San Fernando de Apure in relation to Mantecal?

San Fernando de Apure is located 188 km east of Mantecal.

San Fernando de Apure has geographic coordinates: latitude 7.87879, longitude -67.47178.

Mantecal has geographic coordinates: latitude 7.56652, longitude -69.14705.

Which highway goes from San Fernando de Apure to Mantecal?

The route from San Fernando de Apure to Mantecal follows T-19.

Other minor sections pass along the road:

  • T-02: 7 km
The distance between San Fernando de Apure and Mantecal is ranked 10th in the ranking popularity.
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