Distance between Sebastopol and Linton
The distance from Sebastopol to Linton is 29 kilometers by road. Road takes approximately 47 minutes.
| Shortest distance by air | 26 km ✈️ |
| Car route length | 29 km 🚗 |
| Driving time | 47 min |
| Fuel amount | 2.3 L |
| Fuel cost | 3.8 AUD |
| Point | Distance | Time | Fuel | |
| Sebastopol | 0 km | 00 min | 0.0 L | |
|
B160 29 km, 47 min
|
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| Linton | 29 km | 47 min | 2.1 L | |
Frequently Asked Questions
How much does it cost to drive from Sebastopol to Linton?
Fuel cost: 3.8 AUD
This fuel cost is calculated as: (Route length 29 km / 100 km) * (Fuel consumption 8 L/100 km) * (Fuel price 1.64 AUD / L)
You can adjust fuel consumption and fuel price here.
How long is a car ride from Sebastopol to Linton?
Driving time: 47 min
This time is calculated for driving at the maximum permitted speed, taking into account traffic rules restrictions.
- 9 km with a maximum speed 90 km/h = 6 min
- 5 km with a maximum speed 80 km/h = 3 min
- 2 km with a maximum speed 60 km/h = 1 min
- 1 km with a maximum speed 50 km/h = 1 min
- 11 km with a maximum speed 20 km/h = 33 min
The calculated driving time does not take into account intermediate stops and traffic jams.
How far is Sebastopol to Linton by land?
The distance between Sebastopol and Linton is 29 km by road.
Precise satellite coordinates of highways were used for this calculation. The start and finish points are the centers of Sebastopol and Linton respectively.
Where is Sebastopol in relation to Linton?
Sebastopol is located 26 km north-east of Linton.
Sebastopol has geographic coordinates: latitude -37.59868, longitude 143.83588.
Linton has geographic coordinates: latitude -37.68699, longitude 143.56213.
Which highway goes from Sebastopol to Linton?
The route from Sebastopol to Linton follows B160.